(2y^3+y^2+1)+(3y^3-y^2+2)=

Solution for (2y^3+y^2+1)+(3y^3-y^2+2)= equation:

Simplifying
(2y3 + y2 + 1) + (3y3 + -1y2 + 2) = 0

Reorder the terms:
(1 + y2 + 2y3) + (3y3 + -1y2 + 2) = 0

Remove parenthesis around (1 + y2 + 2y3)
1 + y2 + 2y3 + (3y3 + -1y2 + 2) = 0

Reorder the terms:
1 + y2 + 2y3 + (2 + -1y2 + 3y3) = 0

Remove parenthesis around (2 + -1y2 + 3y3)
1 + y2 + 2y3 + 2 + -1y2 + 3y3 = 0

Reorder the terms:
1 + 2 + y2 + -1y2 + 2y3 + 3y3 = 0

Combine like terms: 1 + 2 = 3
3 + y2 + -1y2 + 2y3 + 3y3 = 0

Combine like terms: y2 + -1y2 = 0
3 + 0 + 2y3 + 3y3 = 0
3 + 2y3 + 3y3 = 0

Combine like terms: 2y3 + 3y3 = 5y3
3 + 5y3 = 0

Solving
3 + 5y3 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 5y3 = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 5y3 = 0 + -3
5y3 = 0 + -3

Combine like terms: 0 + -3 = -3
5y3 = -3

Divide each side by '5'.
y3 = -0.6

Simplifying
y3 = -0.6

Reorder the terms:
0.6 + y3 = -0.6 + 0.6

Combine like terms: -0.6 + 0.6 = 0.0
0.6 + y3 = 0.0

The solution to this equation could not be determined.